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stachulemko edited this page Jun 24, 2024
·
1 revision
for (int i = 0; i < n1; ++i) {
[&] {
for (int j = 0; j < n2; ++j) {
for (int k = 0; k < n3; ++k) {
return; // yay we're breaking out of 2 loops here
}
}
}();
}
for (int i = 0; i < n1; ++i) {
for (int j = 0; j < n2; ++j) {
for (int k = 0; k < n3; ++k) {
goto mainloop;
}
}
mainloop :
}