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We are aware of the method, and it is pretty cool indeed. However, most people are not willing to take their machine apart to test the inertia of the flywheel. For most commercial machines, people choose to adjust the inertia experimentally to match their expected power/speed. |
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I tried this method and I got a negative value, do you have any idea what could be wrong with my measurement? M = 5.2 kg (not super accurate unfortunately, my kitchen scales error at 5kg so this is measured on my bathroom scale) ==> I = -0.5575 ??? |
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Hi,
I don’t remember very Well all step. But i suggest you to Try With more
accurate value M,L,T
And double check the formula.
Il giorno sab 26 ott 2024 alle 01:33 KjellVerb ***@***.***>
ha scritto:
… I tried this method and I got a negative value, do you have any idea what
could be wrong with my measurement?
M = 5.2 kg (not super accurate unfortunately, my kitchen scales error at
5kg so this is measured on my bathroom scale)
L = 3.085
T = 3.5 (10 swings in 35sec)
==> I = -0.5575 ???
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The physics link has a link with D.Vernooy doc https://dvernooy.github.io/projects/ergware/
With Dave I tested another way to find Flywheel Inertia, I tested my flywheel in both way and the result is quite the same, but this solution is more simple (in my opinion).
The formula derived from the "parallel axis theorem". (provided me from Dave Vernooy)
My test
using my stopwatch I get 5.28 seconds for 2 swings back and forth. So this means T = 5.28/2 = 2.64 seconds. With M = 1.91 kg and L = 1.71M, here is what I calculate from my formula:
I = 0.249 * M * L* T^2 - M * L^2
= 0.2491.911.712.64^2 - 1.911.71^2
= 0.2491.911.712.642.64 - 1.911.711.71
= 5.66808 - 5.585031
= 0.083 kg*m^2
So I = 0.08 kg*m^2 for flywheel. Very similar to spreadsheet.
video_2023-01-13_08-55-32.mp4
I hope it can be useful for someone
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